c窗体小游戏源代码（C#控制台小游戏）

今天给各位分享c窗体小游戏源代码的知识，其中也会对C#控制台小游戏进行解释，如果能碰巧解决你现在面临的问题，别忘了关注本站，现在开始吧！

本文目录一览：

• 1、求一些C语言小游戏的源代码，谢谢
• 2、(完整word版)纯C语言写的一个小型游戏 源代码
• 3、求C语言小游戏源程序

求一些C语言小游戏的源代码，谢谢

“推箱子”C代码：

#include stdio.h

#include conio.h

#includestdlib.h

#includewindows.h

int m =0;  //m代表第几关

struct maps{short a[9][11]; };

struct maps map[5]={ 0,0,0,0,0,0,0,0,0,0,0,  //共5关,每关9行11列

              0,1,1,1,1,1,1,1,0,0,0,

              0,1,0,0,0,0,0,1,1,1,0,

              1,1,4,1,1,1,0,0,0,1,0,  //0空地,1墙

               1,5,0,0,4,0,0,4,0,1,0,  //4是箱子,5是人

              1,0,3,3,1,0,4,0,1,1,0,  //3是目的地

              1,1,3,3,1,0,0,0,1,0,0,  //7是箱子在目的地(4+3)

              0,1,1,1,1,1,1,1,1,0,0,  //8是人在目的地(5+3)

                0,0,0,0,0,0,0,0,0,0,0,

                0,0,0,0,0,0,0,0,0,0,0,

              0,0,1,1,1,1,0,0,0,0,0,

              0,0,1,5,0,1,1,1,0,0,0,

              0,0,1,0,4,0,0,1,0,0,0,

               0,1,1,1,0,1,0,1,1,0,0,

              0,1,3,1,0,1,0,0,1,0,0,

              0,1,3,4,0,0,1,0,1,0,0,

              0,1,3,0,0,0,4,0,1,0,0,

                0,1,1,1,1,1,1,1,1,0,0,

                0,0,0,0,0,0,0,0,0,0,0,

              0,0,0,1,1,1,1,1,1,1,0,

              0,0,1,1,0,0,1,0,5,1,0,

              0,0,1,0,0,0,1,0,0,1,0,

               0,0,1,4,0,4,0,4,0,1,0,

              0,0,1,0,4,1,1,0,0,1,0,

              1,1,1,0,4,0,1,0,1,1,0,

              1,3,3,3,3,3,0,0,1,0,0,

                1,1,1,1,1,1,1,1,1,0,0,

                0,1,1,1,1,1,1,1,1,1,0,

              0,1,0,0,1,1,0,0,0,1,0,

              0,1,0,0,0,4,0,0,0,1,0,

              0,1,4,0,1,1,1,0,4,1,0,

               0,1,0,1,3,3,3,1,0,1,0,

              1,1,0,1,3,3,3,1,0,1,1,

              1,0,4,0,0,4,0,0,4,0,1,

              1,0,0,0,0,0,1,0,5,0,1,

                1,1,1,1,1,1,1,1,1,1,1,

                0,0,0,0,0,0,0,0,0,0,0,

              0,0,0,1,1,1,1,1,1,0,0,

              0,1,1,1,0,0,0,0,1,0,0,

              1,1,3,0,4,1,1,0,1,1,0,

               1,3,3,4,0,4,0,0,5,1,0,

              1,3,3,0,4,0,4,0,1,1,0,

              1,1,1,1,1,1,0,0,1,0,0,

              0,0,0,0,0,1,1,1,1,0,0,

               0,0,0,0,0,0,0,0,0,0,0 };

void DrMap( )  //绘制地图

{ CONSOLE_CURSOR_INFO cursor_info={1,0};   //隐藏光标的设置

SetConsoleCursorInfo(GetStdHandle(STD_OUTPUT_HANDLE),cursor_info);

printf("\n\n \t\t\b推箱子");

printf("\n \t");

for (int i = 0; i 9; i++)

{for (int j = 0; j 11; j++)

{switch (map[m].a[i][j])

{case 0:  printf("  "); break;

case 1:  printf("■"); break;

      case 3:  printf("◎");break;

case 4:  printf("□"); break;

case 5:  printf("♀"); break;   //5是人

case 7:  printf("□"); break;  //4 + 3箱子在目的地中

case 8:  printf("♀");break;   // 5 + 3人在目的地中

}

}

printf("\n\t");

}

}

void gtxy(int x, int y)  //控制光标位置的函数

{ COORD coord;

coord.X = x;

coord.Y = y;

SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), coord);

}

void start( )  //开始游戏

{ int r, c;  //人的下标

for (int i = 0; i 9; i++)

{ for (int j = 0; j 11; j++)

{if (map[m].a[i][j] == 5||map[m].a[i][j]==8) { r = i;  c = j; } } //i j 人的下标

}

char key;

key = getch( );

switch (key)

{case 'W':

case 'w':

case 72:

if (map[m]. a[r - 1][c] == 0|| map[m]. a [r - 1][c] == 3)

{ gtxy(2*c+8,r-1+3); printf("♀");  // gtxy(2*c+8,r-1+3)是到指定位置输出字符

       if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf("  "); }

       if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}

        map[m]. a [r - 1][c] += 5;  map[m]. a [r][c] -= 5; }

     else  if (map[m]. a [r - 1][c] == 4 || map[m]. a [r - 1][c] == 7)

{ if (map[m]. a [r - 2][c] == 0 || map[m]. a [r - 2][c] == 3)

{ gtxy(2*c+8,r-2+3); printf("□"); gtxy(2*c+8,r-1+3); printf("♀");

           if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf("  "); }

          if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}

          map[m]. a [r - 2][c] += 4;  map[m]. a [r - 1][c] += 1;

 map[m]. a [r][c] -= 5; }

} break;

case 'S':

case 's':

case 80:

if (map[m]. a [r + 1][c] == 0 || map[m]. a [r + 1][c] == 3)

 { gtxy(2*c+8,r+1+3); printf("♀");

         if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf("  "); }

        if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}

        map[m]. a [r + 1][c] += 5;  map[m]. a [r][c] -= 5; }

       else if (map[m]. a [r + 1][c] == 4 || map[m]. a [r+ 1][c] == 7)

  { if (map[m]. a [r + 2][c] == 0 || map[m]. a [r + 2][c] == 3)

{ gtxy(2*c+8,r+2+3); printf("□"); gtxy(2*c+8,r+1+3); printf("♀");

           if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf("  "); }

           if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}

           map[m]. a [r + 2][c] += 4; map[m]. a [r + 1][c] += 1;

map[m]. a [r][c] -= 5; }

  }break;

case 'A':

case 'a':

case 75:

if (map[m]. a [r ][c - 1] == 0 || map[m]. a [r ][c - 1] == 3)

 { gtxy(2*(c-1)+8,r+3); printf("♀");

        if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf("  "); }

         if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}

        map[m]. a [r ][c - 1] += 5; map[m]. a [r][c] -= 5; }

else if (map[m]. a [r][c - 1] == 4 || map[m]. a [r][c - 1] == 7)

 {if (map[m]. a [r ][c - 2] == 0 || map[m]. a [r ][c - 2] == 3)

{ gtxy(2*(c-2)+8,r+3); printf("□"); gtxy(2*(c-1)+8,r+3); printf("♀");

           if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf("  "); }

           if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}

           map[m]. a [r ][c - 2] += 4; map[m]. a [r ][c - 1] += 1;

map[m]. a [r][c] -= 5; }

 }break;

case 'D':

case 'd':

case 77:

if (map[m]. a [r][c + 1] == 0 || map[m]. a [r][c + 1] == 3)

 { gtxy(2*(c+1)+8,r+3); printf("♀");

         if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf("  "); }

         if(map[m]. a[r ][c] == 8) {gtxy(2*c+8,r+3); printf("◎");}

        map[m]. a [r][c + 1] += 5;  map[m]. a [r][c] -= 5; }

else if (map[m]. a [r][c + 1] == 4 || map[m]. a [r][c + 1] == 7)

 { if (map[m]. a [r][c + 2] == 0 || map[m]. a [r][c + 2] == 3)

{ gtxy(2*(c+2)+8,r+3); printf("□"); gtxy(2*(c+1)+8,r+3); printf("♀");

           if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf("  "); }

          if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}

          map[m]. a [r][c + 2] += 4; map[m]. a [r][c + 1] += 1;

 map[m]. a [r][c] -= 5; }

 }break;

}

}

int ifwan( )  //是否完成(1是0否)

{ if(m==0){if(map[m].a[5][2]==7 map[m].a[5][3]==7

map[m].a[6][2]==7 map[m].a[6][3]==7) return 1;}

if(m==1){if(map[m].a[5][2]==7 map[m].a[6][2]==7

map[m].a[7][2]==7) return 1;}

if(m==2){if(map[m].a[7][1]==7 map[m].a[7][2]==7 map[m].a[7][3]==7

map[m].a[7][4]==7 map[m].a[7][5]==7) return 1;}

if(m==3){if(map[m].a[4][4]==7 map[m].a[4][5]==7 map[m].a[4][6]==7

map[m].a[5][4]==7 map[m].a[5][5]==7 map[m].a[5][6]==7) return 1;}

if(m==4){if(map[m].a[3][2]==7 map[m].a[4][1]==7 map[m].a[4][2]==7

map[m].a[5][1]==7 map[m].a[5][2]==7) return 1;}

return 0;

}

int main( )  //主函数

{ while (1)

     { system("cls");

       DrMap( );

      while (1)

            { start( );

              if(ifwan()){printf("\007");break;} //完成后响铃

           }

       m+=1;

     }

  return 0;

}

(完整word版)纯C语言写的一个小型游戏 源代码

"扫雷"小游戏C代码

#includestdio.h

#includemath.h

#includetime.h

#includestdlib.h

main( )

{char a[102][102],b[102][102],c[102][102],w;

int i,j;  /*循环变量*/

int x,y,z[999];  /*雷的位置*/

int t,s;  /*标记*/

int m,n,lei;  /*计数*/

int u,v;  /*输入*/

int hang,lie,ge,mo;  /*自定义变量*/

srand((int)time(NULL));  /*启动随机数发生器*/

leb1:  /*选择模式*/

printf("\n   请选择模式：\n   1.标准  2.自定义\n");

scanf("%d",mo);

if(mo==2)  /*若选择自定义模式，要输入三个参数*/

{do

{t=0; printf("请输入\n行数 列数 雷的个数\n");

scanf("%d%d%d",hang,lie,ge);

if(hang2){printf("行数太少\n"); t=1;}

if(hang100){printf("行数太多\n");t=1;}

if(lie2){printf("列数太少\n");t=1;}

if(lie100){printf("列数太多\n");t=1;}

if(ge1){printf("至少要有一个雷\n");t=1;}

if(ge=(hang*lie)){printf("雷太多了\n");t=1;}

}while(t==1);

}

else{hang=10,lie=10,ge=10;}  /*否则就是选择了标准模式(默认参数)*/

for(i=1;i=ge;i=i+1)  /*确定雷的位置*/

{do

{t=0; z[i]=rand( )%(hang*lie);

for(j=1;ji;j=j+1){if(z[i]==z[j]) t=1;}

}while(t==1);

}

for(i=0;i=hang+1;i=i+1)  /*初始化a,b,c*/

{for(j=0;j=lie+1;j=j+1) {a[i][j]='1'; b[i][j]='1'; c[i][j]='0';} }

for(i=1;i=hang;i=i+1)

{for(j=1;j=lie;j=j+1) {a[i][j]='+';} }

for(i=1;i=ge;i=i+1)  /*把雷放入c*/

{x=z[i]/lie+1; y=z[i]%lie+1; c[x][y]='#';}

for(i=1;i=hang;i=i+1)  /*计算b中数字*/

{for(j=1;j=lie;j=j+1)

{m=48;

if(c[i-1][j-1]=='#')m=m+1; if(c[i][j-1]=='#')m=m+1;

if(c[i-1][j]=='#')m=m+1;  if(c[i+1][j+1]=='#')m=m+1;

if(c[i][j+1]=='#')m=m+1;  if(c[i+1][j]=='#')m=m+1;

if(c[i+1][j-1]=='#')m=m+1; if(c[i-1][j+1]=='#')m=m+1;

b[i][j]=m;

}

}

for(i=1;i=ge;i=i+1)  /*把雷放入b中*/

{x=z[i]/lie+1; y=z[i]%lie+1; b[x][y]='#';}

lei=ge;  /*以下是游戏设计*/

do

{leb2:  /*输出*/

system("cls");printf("\n\n\n\n");

printf("    ");

for(i=1;i=lie;i=i+1)

{w=(i-1)/10+48; printf("%c",w);

w=(i-1)%10+48; printf("%c  ",w);

}

printf("\n   |");

for(i=1;i=lie;i=i+1){printf("---|");}

printf("\n");

for(i=1;i=hang;i=i+1)

{w=(i-1)/10+48; printf("%c",w);

w=(i-1)%10+48; printf("%c |",w);

for(j=1;j=lie;j=j+1)

{if(a[i][j]=='0')printf("   |");

else printf(" %c |",a[i][j]);

}

if(i==2)printf(" 剩余雷个数");

if(i==3)printf(" %d",lei);

printf("\n   |");

for(j=1;j=lie;j=j+1){printf("---|");}

printf("\n");

}

scanf("%d%c%d",u,w,v);  /*输入*/

u=u+1,v=v+1;

if(w!='#'a[u][v]=='@')

goto leb2;

if(w=='#')

{if(a[u][v]=='+'){a[u][v]='@'; lei=lei-1;}

else if(a[u][v]=='@'){a[u][v]='?'; lei=lei+1;}

else if(a[u][v]=='?'){a[u][v]='+';}

goto leb2;

}

a[u][v]=b[u][v];

leb3:  /*打开0区*/

t=0;

if(a[u][v]=='0')

{for(i=1;i=hang;i=i+1)

{for(j=1;j=lie;j=j+1)

{s=0;

if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;

if(a[i-1][j]=='0')s=1;  if(a[i+1][j-1]=='0')s=1;

if(a[i+1][j+1]=='0')s=1; if(a[i+1][j]=='0')s=1;

if(a[i][j-1]=='0')s=1;  if(a[i][j+1]=='0')s=1;

if(s==1)a[i][j]=b[i][j];

}

}

for(i=1;i=hang;i=i+1)

{for(j=lie;j=1;j=j-1)

{s=0;

if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;

if(a[i-1][j]=='0')s=1;  if(a[i+1][j-1]=='0')s=1;

if(a[i+1][j+1]=='0')s=1; if(a[i+1][j]=='0')s=1;

if(a[i][j-1]=='0')s=1;   if(a[i][j+1]=='0')s=1;

if(s==1)a[i][j]=b[i][j];

}

}

for(i=hang;i=1;i=i-1)

{for(j=1;j=lie;j=j+1)

{s=0;

if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;

if(a[i-1][j]=='0')s=1;  if(a[i+1][j-1]=='0')s=1;

if(a[i+1][j+1]=='0')s=1; if(a[i+1][j]=='0')s=1;

if(a[i][j-1]=='0')s=1;  if(a[i][j+1]=='0')s=1;

if(s==1)a[i][j]=b[i][j];

}

}

for(i=hang;i=1;i=i-1)

{for(j=lie;j=1;j=j-1)

{s=0;

if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;

if(a[i-1][j]=='0')s=1;  if(a[i+1][j-1]=='0')s=1;

if(a[i+1][j+1]=='0')s=1;if(a[i+1][j]=='0')s=1;

if(a[i][j-1]=='0')s=1;  if(a[i][j+1]=='0')s=1;

if(s==1)a[i][j]=b[i][j];

}

}

for(i=1;i=hang;i=i+1)  /*检测0区*/

{for(j=1;j=lie;j=j+1)

{if(a[i][j]=='0')

{if(a[i-1][j-1]=='+'||a[i-1][j-1]=='@'||a[i-1][j-1]=='?')t=1;

if(a[i-1][j+1]=='+'||a[i-1][j+1]=='@'||a[i-1][j+1]=='?')t=1;

if(a[i+1][j-1]=='+'||a[i+1][j-1]=='@'||a[i+1][j-1]=='?')t=1;

if(a[i+1][j+1]=='+'||a[i+1][j+1]=='@'||a[i+1][j+1]=='?')t=1;

if(a[i+1][j]=='+'||a[i+1][j]=='@'||a[i+1][j]=='?')t=1;

if(a[i][j+1]=='+'||a[i][j+1]=='@'||a[i][j+1]=='?')t=1;

if(a[i][j-1]=='+'||a[i][j-1]=='@'||a[i][j-1]=='?')t=1;

if(a[i-1][j]=='+'||a[i-1][j]=='@'||a[i-1][j]=='?')t=1;

}

}

}

if(t==1)goto leb3;

}

n=0;  /*检查结束*/

for(i=1;i=hang;i=i+1)

{for(j=1;j=lie;j=j+1)

{if(a[i][j]!='+'a[i][j]!='@'a[i][j]!='?')n=n+1;}

}

}

while(a[u][v]!='#'n!=(hang*lie-ge));

for(i=1;i=ge;i=i+1)  /*游戏结束*/

{x=z[i]/lie+1; y=z[i]%lie+1; a[x][y]='#'; }

printf("    ");

for(i=1;i=lie;i=i+1)

{w=(i-1)/10+48; printf("%c",w);

w=(i-1)%10+48; printf("%c  ",w);

}

printf("\n   |");

for(i=1;i=lie;i=i+1){printf("---|");}

printf("\n");

for(i=1;i=hang;i=i+1)

{w=(i-1)/10+48; printf("%c",w);

w=(i-1)%10+48; printf("%c |",w);

for(j=1;j=lie;j=j+1)

{if(a[i][j]=='0')printf(" |");

else  printf(" %c |",a[i][j]);

}

if(i==2)printf(" 剩余雷个数");

if(i==3)printf(" %d",lei); printf("\n   |");

for(j=1;j=lie;j=j+1) {printf("---|");}

printf("\n");

}

if(n==(hang*lie-ge)) printf("你成功了!\n");

else printf("    游戏结束!\n");

printf("    重玩请输入1\n");

t=0;

scanf("%d",t);

if(t==1)goto leb1;

}

/*注：在DEV c++上运行通过。行号和列号都从0开始，比如要确定第0行第9列不是“雷”，就在0和9中间加入一个字母，可以输入【0a9】三个字符再按回车键。3行7列不是雷，则输入【3a7】回车；第8行第5列是雷，就输入【8#5】回车，9行0列是雷则输入【9#0】并回车*/

求C语言小游戏源程序

我的楼主可以自己玩一下

试试吧

#define N 200

#include graphics.h

#include stdlib.h

#include dos.h

#define LEFT 0x4b00

#define RIGHT 0x4d00

#define DOWN 0x5000

#define UP 0x4800

#define ESC 0x011b

int i,key;

int score=0;/*得分*/

int gamespeed=50000;/*游戏速度自己调整*/

struct Food

{

int x;/*食物的横坐标*/

int y;/*食物的纵坐标*/

int yes;/*判断是否要出现食物的变量*/

}food;/*食物的结构体*/

struct Snake

{

int x[N];

int y[N];

int node;/*蛇的节数*/

int direction;/*蛇移动方向*/

int life;/* 蛇的生命,0活着,1死亡*/

}snake;

void Init(void);/*图形驱动*/

void Close(void);/*图形结束*/

void DrawK(void);/*开始画面*/

void GameOver(void);/*结束游戏*/

void GamePlay(void);/*玩游戏具体过程*/

void PrScore(void);/*输出成绩*/

/*主函数*/

void main(void)

{

Init();/*图形驱动*/

DrawK();/*开始画面*/

GamePlay();/*玩游戏具体过程*/

Close();/*图形结束*/

}

/*图形驱动*/

void Init(void)

{

int gd=DETECT,gm;

initgraph(gd,gm,"c:\\tc");

cleardevice();

}

/*开始画面，左上角坐标为（50，40），右下角坐标为（610，460）的围墙*/

void DrawK(void)

{

/*setbkcolor(LIGHTGREEN);*/

setcolor(11);

setlinestyle(SOLID_LINE,0,THICK_WIDTH);/*设置线型*/

for(i=50;i=600;i+=10)/*画围墙*/

{

rectangle(i,40,i+10,49); /*上边*/

rectangle(i,451,i+10,460);/*下边*/

}

for(i=40;i=450;i+=10)

{

rectangle(50,i,59,i+10); /*左边*/

rectangle(601,i,610,i+10);/*右边*/

}

}

/*玩游戏具体过程*/

void GamePlay(void)

{

randomize();/*随机数发生器*/

food.yes=1;/*1表示需要出现新食物,0表示已经存在食物*/

snake.life=0;/*活着*/

snake.direction=1;/*方向往右*/

snake.x[0]=100;snake.y[0]=100;/*蛇头*/

snake.x[1]=110;snake.y[1]=100;

snake.node=2;/*节数*/

PrScore();/*输出得分*/

while(1)/*可以重复玩游戏,压ESC键结束*/

{

while(!kbhit())/*在没有按键的情况下,蛇自己移动身体*/

{

if(food.yes==1)/*需要出现新食物*/

{

food.x=rand()%400+60;

food.y=rand()%350+60;

while(food.x%10!=0)/*食物随机出现后必须让食物能够在整格内,这样才可以让蛇吃到*/

food.x++;

while(food.y%10!=0)

food.y++;

food.yes=0;/*画面上有食物了*/

}

if(food.yes==0)/*画面上有食物了就要显示*/

{

setcolor(GREEN);

rectangle(food.x,food.y,food.x+10,food.y-10);

}

for(i=snake.node-1;i0;i--)/*蛇的每个环节往前移动,也就是贪吃蛇的关键算法*/

{

snake.x[i]=snake.x[i-1];

snake.y[i]=snake.y[i-1];

}

/*1,2,3,4表示右,左,上,下四个方向,通过这个判断来移动蛇头*/

switch(snake.direction)

{

case 1:snake.x[0]+=10;break;

case 2: snake.x[0]-=10;break;

case 3: snake.y[0]-=10;break;

case 4: snake.y[0]+=10;break;

}

for(i=3;isnake.node;i++)/*从蛇的第四节开始判断是否撞到自己了，因为蛇头为两节，第三节不可能拐过来*/

{

if(snake.x[i]==snake.x[0]snake.y[i]==snake.y[0])

{

GameOver();/*显示失败*/

snake.life=1;

break;

}

}

if(snake.x[0]55||snake.x[0]595||snake.y[0]55||

snake.y[0]455)/*蛇是否撞到墙壁*/

{

GameOver();/*本次游戏结束*/

snake.life=1; /*蛇死*/

}

if(snake.life==1)/*以上两种判断以后,如果蛇死就跳出内循环，重新开始*/

break;

if(snake.x[0]==food.xsnake.y[0]==food.y)/*吃到食物以后*/

{

setcolor(0);/*把画面上的食物东西去掉*/

rectangle(food.x,food.y,food.x+10,food.y-10);

snake.x[snake.node]=-20;snake.y[snake.node]=-20;

/*新的一节先放在看不见的位置,下次循环就取前一节的位置*/

snake.node++;/*蛇的身体长一节*/

food.yes=1;/*画面上需要出现新的食物*/

score+=10;

PrScore();/*输出新得分*/

}

setcolor(4);/*画出蛇*/

for(i=0;isnake.node;i++)

rectangle(snake.x[i],snake.y[i],snake.x[i]+10,

snake.y[i]-10);

delay(gamespeed);

setcolor(0);/*用黑色去除蛇的的最后一节*/

rectangle(snake.x[snake.node-1],snake.y[snake.node-1],

snake.x[snake.node-1]+10,snake.y[snake.node-1]-10);

} /*endwhile（！kbhit）*/

if(snake.life==1)/*如果蛇死就跳出循环*/

break;

key=bioskey(0);/*接收按键*/

if(key==ESC)/*按ESC键退出*/

break;

else

if(key==UPsnake.direction!=4)

/*判断是否往相反的方向移动*/

snake.direction=3;

else

if(key==RIGHTsnake.direction!=2)

snake.direction=1;

else

if(key==LEFTsnake.direction!=1)

snake.direction=2;

else

if(key==DOWNsnake.direction!=3)

snake.direction=4;

}/*endwhile(1)*/

}

/*游戏结束*/

void GameOver(void)

{

cleardevice();

PrScore();

setcolor(RED);

settextstyle(0,0,4);

outtextxy(200,200,"GAME OVER");

getch();

}

/*输出成绩*/

void PrScore(void)

{

char str[10];

setfillstyle(SOLID_FILL,YELLOW);

bar(50,15,220,35);

setcolor(6);

settextstyle(0,0,2);

sprintf(str,"score:%d",score);

outtextxy(55,20,str);

}

/*图形结束*/

void Close(void)

{

getch();

closegraph();

}

c窗体小游戏源代码的介绍就聊到这里吧，感谢你花时间阅读本站内容，更多关于C#控制台小游戏、c窗体小游戏源代码的信息别忘了在本站进行查找喔。