mfcrsa源代码(mfc编写)
admin 发布:2022-12-19 19:39 150
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求RSA算法的源代码(c语言)
这个是我帮个朋友写的,写的时候发现其实这个没那么复杂,不过,时间复杂度要高于那些成型了的,为人所熟知的rsa算法的其他语言实现.
#include
int
candp(int
a,int
b,int
c)
{
int
r=1;
b=b+1;
while(b!=1)
{
r=r*a;
r=r%c;
b--;
}
printf("%d",r);
return
r;
}
void
main()
{
int
p,q,e,d,m,n,t,c,r;
char
s;
{printf("input
the
p:\n");
scanf("%d\n",p);
printf("input
the
q:\n");
scanf("%d%d\n",p);
n=p*q;
printf("so,the
n
is
%3d\n",n);
t=(p-1)*(q-1);
printf("so,the
t
is
%3d\n",t);
printf("please
intput
the
e:\n");
scanf("%d",e);
if(e1||et)
{printf("e
is
error,please
input
again;");
scanf("%d",e);}
d=1;
while
(((e*d)%t)!=1)
d++;
printf("then
caculate
out
that
the
d
is
%5d",d);
printf("if
you
want
to
konw
the
cipher
please
input
1;\n
if
you
want
to
konw
the
plain
please
input
2;\n");
scanf("%d",r);
if(r==1)
{
printf("input
the
m
:"
);/*输入要加密的明文数字*/
scanf("%d\n",m);
c=candp(m,e,n);
printf("so
,the
cipher
is
%4d",c);}
if(r==2)
{
printf("input
the
c
:"
);/*输入要解密的密文数字*/
scanf("%d\n",c);
m=candp(c,d,n);
printf("so
,the
cipher
is
%4d\n",m);
printf("do
you
want
to
use
this
programe:yes
or
no");
scanf("%s",s);
}while(s=='y');
}
}
用C++写出如下RSA加密算法
#include iostream
using namespace std;
template class HugeInt
HugeInt Power( const HugeInt x, const HugeInt n, // 求x^n mod p
const HugeInt p )
{
if( n == 0 )
return 1;
HugeInt tmp = Power( ( x * x ) % p, n / 2, p );
if( n % 2 != 0 )
tmp = ( tmp * x ) % p;
return tmp;
}
template class HugeInt
void fullGcd( const HugeInt a, const HugeInt b, //
HugeInt x, HugeInt y )
{
HugeInt x1, y1;
if( b == 0 )
{
x = 1;
y = 0;
}
else
{
fullGcd( b, a % b, x1, y1 );
x = y1;
y = x1 - ( a / b ) * y1;
}
}
template class HugeInt
HugeInt inverse( const HugeInt p, const HugeInt q, // 求d
const HugeInt e )
{
int fyn = ( 1 - p ) * ( 1 - q );
HugeInt x, y;
fullGcd( fyn, e, x, y );
return x 0 ? x : x + e;
}
int main( )
{
cout "Please input the plaintext: " endl;
int m;
cin m;
cout "Please input p,q and e: " endl;
int p, q, e;
cin p q e;
int n = p * q;
int d = inverse( p, q, e );
int C = Power( m, e, n );
cout "The ciphertext is: " C endl;
cout "\n\nPlease input the ciphertext: " endl;
cin C;
cout "\n\nPlease input p, q and d: " endl;
cin p q d;
n = p * q;
m = Power( C, d, n );
cout "The plaintext is: " m endl endl;
system( "pause" );
return 0;
}
求RSA加密解密算法,c++源代码
//下面程序由520huiqin编写,已在VC++ 6.0下编译通过
#include iostream.h
#include math.h
#include stdio.h
typedef int Elemtype;
Elemtype p,q,e;
Elemtype fn;
Elemtype m,c;
int flag = 0;
typedef void (*Msghandler) (void);
struct MsgMap {
char ch;
Msghandler handler;
};
/* 公钥 */
struct PU {
Elemtype e;
Elemtype n;
} pu;
/* 私钥 */
struct PR {
Elemtype d;
Elemtype n;
} pr;
/* 判定一个数是否为素数 */
bool test_prime(Elemtype m) {
if (m = 1) {
return false;
}
else if (m == 2) {
return true;
}
else {
for(int i=2; i=sqrt(m); i++) {
if((m % i) == 0) {
return false;
break;
}
}
return true;
}
}
/* 将十进制数据转化为二进制数组 */
void switch_to_bit(Elemtype b, Elemtype bin[32]) {
int n = 0;
while( b 0) {
bin[n] = b % 2;
n++;
b /= 2;
}
}
/* 候选菜单,主界面 */
void Init() {
cout"*********************************************"endl;
cout"*** Welcome to use RSA encoder ***"endl;
cout"*** a.about ***"endl;
cout"*** e.encrypt ***"endl;
cout"*** d.decrypt ***"endl;
cout"*** s.setkey ***"endl;
cout"*** q.quit ***"endl;
cout"**********************************by*Terry***"endl;
cout"press a key:"endl;
}
/* 将两个数排序,大的在前面*/
void order(Elemtype in1, Elemtype in2) {
Elemtype a = ( in1 in2 ? in1 : in2);
Elemtype b = ( in1 in2 ? in1 : in2);
in1 = a;
in2 = b;
}
/* 求最大公约数 */
Elemtype gcd(Elemtype a, Elemtype b) {
order(a,b);
int r;
if(b == 0) {
return a;
}
else {
while(true) {
r = a % b;
a = b;
b = r;
if (b == 0) {
return a;
break;
}
}
}
}
/* 用扩展的欧几里得算法求乘法逆元 */
Elemtype extend_euclid(Elemtype m, Elemtype bin) {
order(m,bin);
Elemtype a[3],b[3],t[3];
a[0] = 1, a[1] = 0, a[2] = m;
b[0] = 0, b[1] = 1, b[2] = bin;
if (b[2] == 0) {
return a[2] = gcd(m, bin);
}
if (b[2] ==1) {
return b[2] = gcd(m, bin);
}
while(true) {
if (b[2] ==1) {
return b[1];
break;
}
int q = a[2] / b[2];
for(int i=0; i3; i++) {
t[i] = a[i] - q * b[i];
a[i] = b[i];
b[i] = t[i];
}
}
}
/* 快速模幂算法 */
Elemtype modular_multiplication(Elemtype a, Elemtype b, Elemtype n) {
Elemtype f = 1;
Elemtype bin[32];
switch_to_bit(b,bin);
for(int i=31; i=0; i--) {
f = (f * f) % n;
if(bin[i] == 1) {
f = (f * a) % n;
}
}
return f;
}
/* 产生密钥 */
void produce_key() {
cout"input two primes p and q:";
cinpq;
while (!(test_prime(p)test_prime(q))){
cout"wrong input,please make sure two number are both primes!"endl;
cout"input two primes p and q:";
cinpq;
};
pr.n = p * q;
pu.n = p * q;
fn = (p - 1) * (q - 1);
cout"fn = "fnendl;
cout"input e :";
cine;
while((gcd(fn,e)!=1)) {
cout"e is error,try again!";
cout"input e :";
cine;
}
pr.d = (extend_euclid(fn,e) + fn) % fn;
pu.e = e;
flag = 1;
cout"PR.d: "pr.d" PR.n: "pr.nendl;
cout"PU.e: "pu.e" PU.n: "pu.nendl;
}
/* 加密 */
void encrypt() {
if(flag == 0) {
cout"setkey first:"endl;
produce_key();
}
cout"input m:";
cinm;
c = modular_multiplication(m,pu.e,pu.n);
cout"c is:"cendl;
}
/* 解密 */
void decrypt() {
if(flag == 0) {
cout"setkey first:"endl;
produce_key();
}
cout"input c:";
cinc;
m = modular_multiplication(c,pr.d,pr.n);
cout"m is:"mendl;
}
/* 版权信息 */
void about() {
cout"*********************************************"endl;
cout"*** by Terry ***"endl;
cout"*** copyright 2010,All rights reserved by ***"endl;
cout"*** Terry,technology supported by weizuo !***"endl;
cout"*** If you have any question, please mail ***"endl;
cout"*** to 18679376@qq.com ! ***"endl;
cout"*** Computer of science and engineering ***"endl;
cout"*** XiDian University 2010-4-29 ***"endl;
cout"*********************************************"endl;
coutendlendl;
Init();
}
/* 消息映射 */
MsgMap Messagemap[] = {
{'a',about},
{'s',produce_key},
{'d',decrypt},
{'e',encrypt},
{'q',NULL}
};
/* 主函数,提供循环 */
void main() {
Init();
char d;
while((d = getchar())!='q') {
int i = 0;
while(Messagemap[i].ch) {
if(Messagemap[i].ch == d) {
Messagemap[i].handler();
break;
}
i++;
}
}
}
//欢迎分享,盗窃可耻
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