2048安卓源代码(2048程序)[20240420更新]
admin 发布:2024-04-20 21:30 120
本篇文章给大家谈谈2048安卓源代码,以及2048程序对应的知识点,希望对各位有所帮助,不要忘了收藏本站喔。
本文目录一览:
- 1、python小游戏2048,上班摸鱼必备(附源码)
- 2、求2048朝代版的源代码?
- 3、2048游戏链接地址。
- 4、2048游戏怎么玩?
- 5、c语言猜数字游戏源代码
- 6、急求游戏2048源代码,要求使用C++和HGE编写,充分体现面向对象编程的特点。
python小游戏2048,上班摸鱼必备(附源码)
话不多说,直接上菜
为了方便大家copy,我就不分段解释了
import turtle, random
# 定义一个类,用来画除了数字方块之外的图形
class BackGround(turtle.Turtle):
def __init__(self):
super().__init__()
self.penup()
self.ht()
def draw_block(self):
self.shape('bg.gif') # 画出背景方块
for i in allpos:
self.goto(i)
self.stamp()
self.color('white', 'white') # 画出其他背景
self.goto(-215, 120)
self.begin_fill()
self.goto(215, 120)
self.goto(215, 110)
self.goto(-215, 110)
self.end_fill()
self.shape('title.gif')
self.goto(-125, 210)
self.stamp()
self.shape('score.gif')
self.goto(125, 245)
self.stamp()
self.shape('top_score.gif')
self.goto(125, 170)
self.stamp()
# 游戏失败及达成2048的提示文字
def judge(self):
global flag_win, flag_win_lose_text
self.color('blue')
judge = 0 # 判断是否还有位置可以移动
for i in block_dic.values():
for j in block_dic.values():
if i.num == 0 or i.num == j.num and i.distance(j) == 100:
judge += 1
if judge == 0: # 无位置可移动,游戏失败
self.write(' GAME OVER\n重新开始请按空格键', align='center', font=('黑体', 30, 'bold'))
flag_win_lose_text = False
if flag_win is True: # 此条件让2048达成的判断只能进行一次
for k in block_dic.values():
if k.num == 2048: # 游戏达成
flag_win = False
self.write(' 达成2048\n继续游戏请按回车键', align='center', font=('黑体', 30, 'bold'))
flag_win_lose_text = False
def win_lose_clear(self):
global flag_win_lose_text
self.clear()
flag_win_lose_text = True
def show_score(self): # 分值的显示
global score, top_score
if score top_score:
top_score = score
with open('.\\score.txt', 'w') as f:
f.write(f'{top_score}')
self.color('white')
self.goto(125, 210)
self.clear()
self.write(f'{score}', align='center', font=('Arial', 20, 'bold'))
self.goto(125, 135)
self.write(f'{top_score}', align='center', font=('Arial', 20, 'bold'))
# 数字方块类
class Block(turtle.Turtle):
def __init__(self):
super().__init__()
self.ht()
self.penup()
self.num = 0
def draw(self):
self.clear()
dic_draw = {2: '#eee6db', 4: '#efe0cd', 8: '#f5af7b',
16: '#fb9660', 32: '#f57d5a', 64: '#f95c3d',
128: '#eccc75', 256: '#eece61', 512: '#efc853',
1024: '#ebc53c', 2048: '#eec430', 4096: '#aeb879',
8192: '#aab767', 16384: '#a6b74f'}
if self.num 0: # 数字大于0,画出方块
self.color(f'{dic_draw[self.num]}') # 选择颜色
self.begin_fill()
self.goto(self.xcor()+48, self.ycor()+48)
self.goto(self.xcor()-96, self.ycor())
self.goto(self.xcor(), self.ycor()-96)
self.goto(self.xcor()+96, self.ycor())
self.goto(self.xcor(), self.ycor()+96)
self.end_fill()
self.goto(self.xcor()-48, self.ycor()-68)
if self.num 4: # 按照数字选择数字的颜色
self.color('white')
else:
self.color('#6d6058')
self.write(f'{self.num}', align='center', font=('Arial', 27, 'bold'))
self.goto(self.xcor(), self.ycor()+20)
class Game():
def init(self):
back = BackGround() # 实例画出游戏的背景
back.draw_block()
for i in allpos: # 画出16个海龟对应16个数字块
block = Block()
block.goto(i)
block_dic[i] = block
game.grow()
def restart(self): # 重开游戏的方法
global score, flag_win_lose_text
score = 0
for i in block_dic.values():
i.num = 0
i.clear()
win_lose_text.clear()
game.grow()
flag_win_lose_text = True # 此flag为游戏达成或失败出现提示语后的判断,要提示语被clear后才能继续move
def grow(self): # 随机出现一个2或4的数字块
block_list = []
for i in allpos:
if block_dic[i].num == 0:
block_list.append(block_dic[i]) # 挑出空白方块的海龟
turtle_choice = random.choice(block_list) # 随机选中其中一个海龟
turtle_choice.num = random.choice([2, 2, 2, 2, 4]) # 赋属性num=2/4
turtle_choice.draw()
win_lose_text.judge()
show_score_text.show_score()
ms.update()
def move_up(self):
allpos1 = allpos[::4] # 切片为四列
allpos2 = allpos[1::4]
allpos3 = allpos[2::4]
allpos4 = allpos[3::4]
self.move_move(allpos1, allpos2, allpos3, allpos4)
def move_down(self):
allpos1 = allpos[-4::-4]
allpos2 = allpos[-3::-4]
allpos3 = allpos[-2::-4]
allpos4 = allpos[-1::-4]
self.move_move(allpos1, allpos2, allpos3, allpos4)
def move_left(self):
allpos1 = allpos[:4]
allpos2 = allpos[4:8]
allpos3 = allpos[8:12]
allpos4 = allpos[12:16]
self.move_move(allpos1, allpos2, allpos3, allpos4)
def move_right(self):
allpos1 = allpos[-1:-5:-1]
allpos2 = allpos[-5:-9:-1]
allpos3 = allpos[-9:-13:-1]
allpos4 = allpos[-13:-17:-1]
self.move_move(allpos1, allpos2, allpos3, allpos4)
def move_move(self, allpos1, allpos2, allpos3, allpos4):
if flag_win_lose_text is True:
count1 = self.move(allpos1) # 四列或四行依次移动
count2 = self.move(allpos2)
count3 = self.move(allpos3)
count4 = self.move(allpos4)
if count1 or count2 or count3 or count4: # 判断是否有方块移动,有才能继续出现新的数字块
self.grow()
def move(self, pos_list):
num_list = [] # 为某一列或行的数字块海龟的坐标
for i in pos_list:
num_list.append(block_dic[i].num) # 把这些海龟的NUM形成list
new_num_list, count = self.list_oper(num_list) # 只是list_oper的方法形成新的list
for j in range(len(new_num_list)): # 把新的list依次赋值给对应的海龟.num属性并调用draw()方法
block_dic[pos_list[j]].num = new_num_list[j]
block_dic[pos_list[j]].draw()
return count
def list_oper(self, num_list): # num_list的操作,假设其为【2,0,2,2】
global score
count = True
temp = []
new_temp = []
for j in num_list:
if j != 0:
temp.append(j) # temp=[2,2,2]
flag = True
for k in range(len(temp)):
if flag:
if k len(temp)-1 and temp[k] == temp[k+1]:
new_temp.append(temp[k]*2)
flag = False
score += temp[k]
else:
new_temp.append(temp[k]) # new_temp=[4,2]
else:
flag = True
for m in range(len(num_list)-len(new_temp)):
new_temp.append(0) # new_temp=[4,2,0,0]
if new_temp == num_list:
count = False # 此变量判断num_list没有变化,数字块无移动
return(new_temp, count)
if __name__ == '__main__':
ms = turtle.Screen() # 主窗口的设置
ms.setup(430, 630, 400, 50)
ms.bgcolor('gray')
ms.title('2048')
ms.tracer(0)
ms.register_shape('bg.gif')
ms.register_shape('title.gif')
ms.register_shape('score.gif')
ms.register_shape('top_score.gif')
block_dic = {} # 放数字方块海龟的字典,位置坐标为key,对应海龟为value
allpos = [(-150, 50), (-50, 50), (50, 50), (150, 50),
(-150, -50), (-50, -50), (50, -50), (150, -50),
(-150, -150), (-50, -150), (50, -150), (150, -150),
(-150, -250), (-50, -250), (50, -250), (150, -250)]
flag_win = True # 达成2048的判断,让达成的文字仅出现一次
flag_win_lose_text = True # 用来判断失败或成功的提示文字是否有被清除,不清除不能继续移动方块
score = 0
with open('.\\score.txt', 'r') as f:
top_score = int(f.read()) # 读取score中的数据
show_score_text = BackGround()
win_lose_text = BackGround()
game = Game()
game.init()
ms.listen()
ms.onkey(game.move_up, 'Up')
ms.onkey(game.move_down, 'Down')
ms.onkey(game.move_left, 'Left')
ms.onkey(game.move_right, 'Right')
ms.onkey(win_lose_text.win_lose_clear, 'Return')
ms.onkey(game.restart, 'space')
ms.mainloop()
这是游戏界面:
欢迎挑战最高分。
要运行出来,必须本地要有这些文件:bg.gif,score.gif,title.gif,top_score.gif,score.txt
我把这些文件放在了群里,还有一些学习的资料,群号642109462,欢迎对python感兴趣的进群讨论。
支持作者的,可以关注和点赞。感谢你们!
求2048朝代版的源代码?
import javax.swing.*;
import java.awt.*;
@SuppressWarnings("serial")
public class Game_block extends JLabel {
private int value;
public Game_block() {
super("go!");
value = 0;
setFont(new Font("font", Font.PLAIN, 40));
setBackground(Color.black);
}
public int getValue() {
return value;
}
public void setValue(int value) {
this.value = value;
String Text = String.valueOf(value);
if (value != 0){
if(value == 2)
setText("夏");
}
if (value != 0){
if(value == 4)
setText("商");
}
if (value != 0){
if(value == 8)
setText("周");
}
if (value != 0){
if(value == 16)
setText("秦");
}
if (value != 0){
if(value == 32)
setText("汉");
}
if (value != 0){
if(value == 64)
setText("三国");
}
if (value != 0){
if(value == 128)
setText("南北朝");
}
if (value != 0){
if(value == 256)
setText("隋");
}
if (value != 0){
if(value == 1024)
setText("五代十国");
}
if (value != 0){
if(value == 2048)
setText("宋辽");
}
if (value != 0){
if(value == 4096)
setText("宋金");
}
if (value != 0){
if(value == 8192)
setText("元");
}
if (value != 0){
if(value == 16384)
setText("明");
}
if (value != 0){
if(value == 32768)
setText("清");
}
if (value != 0){
if(value == 65536)
setText("现代");
}
else
setText("2048");
setColor();
}
public void setColor() {
if (this.value == 0)
setBackground(Color.black);
else if (this.value == 2)
setBackground(new Color(238, 228, 218));
else if (this.value == 4)
setBackground(new Color(248, 232, 248));
else if (this.value == 8)
setBackground(new Color(243, 177, 116));
else if (this.value == 16)
setBackground(new Color(243, 177, 126));
else if (this.value == 32)
setBackground(new Color(248, 149, 90));
else if (this.value == 64)
setBackground(new Color(249, 94, 50));
else if (this.value == 128)
setBackground(new Color(239, 207, 108));
else if (this.value == 256)
setBackground(new Color(239, 207, 99));
else if (this.value == 512)
setBackground(new Color(239, 203, 82));
else if (this.value == 1024)
setBackground(new Color(239, 199, 57));
else if (this.value == 2048)
setBackground(new Color(239, 195, 41));
else if (this.value == 4096)
setBackground(new Color(255, 60, 57));
else if (this.value == 8192)
setBackground(new Color(258, 60, 59));
else if (this.value == 16384)
setBackground(new Color(262, 62, 59));
else if (this.value == 32768)
setBackground(new Color(262, 64, 62));
else if (this.value == 65536)
setBackground(new Color(264, 64, 66));
}
}
______________________________________________________
import java.awt.*;
import java.awt.event.KeyEvent;
import java.awt.event.KeyListener;
import java.awt.event.MouseAdapter;
import java.awt.event.MouseEvent;
import javax.swing.*;
@SuppressWarnings("serial")
public class Game_my2048 extends JFrame implements KeyListener {
Game_block[] block;
JPanel panel;
boolean numFlag;
int moveFlag;
int a ;//a 的引入是为了防止连加的情况出现
public Game_my2048() {
numFlag = true;
moveFlag = 0;
block = new Game_block[16];
setTitle("2048朝代版");
setSize(400, 400);
setLocation(500, 200);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
panel = (JPanel) getContentPane();
panel.setLayout(new GridLayout(4, 4, 5, 5));
addBlock();
for (int i = 0; i 2; i++)
appearBlock();
this.addKeyListener(this);
this.setVisible(true);
}
public void addBlock() {
for (int i = 0; i 16; i++) {
block[i] = new Game_block();
block[i].setHorizontalAlignment(JLabel.CENTER);
// 不透明
block[i].setOpaque(true);
panel.add(block[i]);
}
}
public void appearBlock() {
while(numFlag) {
int index = (int) (Math.random() * 16);
if (block[index].getValue() == 0) {
if (Math.random() 0.5)
block[index].setValue(2);
else
block[index].setValue(4);
break;
}
}
}
public void judgeAppear() {
int sum = 0;
for (int i = 0; i 16; i++) {
if (block[i].getValue() != 0)
sum++;
}
if (sum == 16)
numFlag = false;
}
public void upBlock() {
for (int i = 12; i 16; i++) {
int index = i;
for (int j = i - 4; j = i - 12; j -= 4) {
int valueI = block[index].getValue(), valueJ = block[j]
.getValue();
if (valueJ == 0) {
block[index].setValue(0);
block[j].setValue(valueI);
} else {
if (valueI == valueJ) {
block[index].setValue(0);
block[j].setValue(valueI + valueJ);
if (valueI + valueJ == 4096)
win();
numFlag = true;
moveFlag = 0;
} else if (numFlag == false)
moveFlag += 1;
}
index = j;
}
}
}
public void downBlock() {
for (int i = 0; i 4; i++) {
a = 5;
int index = i;
for (int j = i + 4; j = i + 12; j += 4) {
int valueI = block[index].getValue(), valueJ = block[j]
.getValue();
if (valueJ == 0) {
block[index].setValue(0);
block[j].setValue(valueI);
} else {
if (valueI == valueJ) {
block[index].setValue(0);
block[j].setValue(valueI + valueJ);
if (valueI + valueJ == 4096)
win();
numFlag = true;
moveFlag = 0;
} else if (numFlag == false)
moveFlag += 1;
}
index = j;
}
}
}
public void rightBlock() {
for (int i = 0; i = 12; i += 4) {
int index = i;
for (int j = i + 1; j = i + 3; j++) {
int valueI = block[index].getValue(), valueJ = block[j]
.getValue();
if (valueJ == 0) {
block[index].setValue(0);
block[j].setValue(valueI);
} else {
if (valueI == valueJ) {
block[index].setValue(0);
block[j].setValue(valueI + valueJ);
if (valueI + valueJ == 4096)
win();
numFlag = true;
moveFlag = 0;
} else if (numFlag == false)
moveFlag += 1;
}
index = j;
}
}
}
public void leftBlock() {
for (int i = 3; i = 15; i += 4) {
int index = i;
for (int j = i - 1; j = i - 3; j--) {
int valueI = block[index].getValue(), valueJ = block[j]
.getValue();
if (valueJ == 0) {
block[index].setValue(0);
block[j].setValue(valueI);
} else {
if (valueI == valueJ) {
block[index].setValue(0);
block[j].setValue(valueI + valueJ);
if (valueI + valueJ == 4096)
win();
numFlag = true;
moveFlag = 0;
} else if (numFlag == false)
moveFlag += 1;
}
index = j;
}
}
}
@Override
public void keyPressed(KeyEvent e) {
switch (e.getKeyCode()) {
case KeyEvent.VK_UP:
upBlock();
judgeAppear();
appearBlock();
over();
break;
case KeyEvent.VK_DOWN:
downBlock();
judgeAppear();
appearBlock();
over();
break;
case KeyEvent.VK_LEFT:
leftBlock();
judgeAppear();
appearBlock();
over();
break;
case KeyEvent.VK_RIGHT:
rightBlock();
judgeAppear();
appearBlock();
over();
break;
}
}
public void over() {
if (!numFlag moveFlag = 36) {
block[4].setText("G");
block[5].setText("A");
block[6].setText("M");
block[7].setText("E");
block[8].setText("O");
block[9].setText("V");
block[10].setText("E");
block[11].setText("R");
block[11].addMouseListener(new MouseAdapter() {
@Override
public void mousePressed(MouseEvent e) {
reStart();
}
});
}
}
public void win() {
block[0].setText("Y");
block[1].setText("O");
block[2].setText("U");
block[13].setText("W");
block[14].setText("I");
block[15].setText("N");
block[15].addMouseListener(new MouseAdapter() {
@Override
public void mousePressed(MouseEvent e) {
reStart();
}
});
}
public void reStart(){
numFlag=true;
moveFlag=0;
for(int i=0;i 16;i++)
block[i].setValue(0);
for (int i = 0; i 2; i++)
appearBlock();
}
@Override
public void keyTyped(KeyEvent e) {
}
@Override
public void keyReleased(KeyEvent e) {
}
public static void main(String args[]) {
JFrame.setDefaultLookAndFeelDecorated(true);
new Game_my2048();
}
}
__________________________________________________________________________
这个代码却少很多功能的
2048游戏链接地址。
如果你是安卓用户,这是我个人收集的全部2048信息,望采纳
360:
可以保存的2048 (SL大法)
2048六边形 (= =! 和正方形感觉不一样,很难死)
安智
(六边形)
5X5 2048(更加时间杀手)
元素周期表 (学霸必备,本学渣泪目 T T)
海外党の福利 (google play):
普通带保存(还是SL)
斐波那契(for 数学爱好者)
5X5
2048游戏怎么玩?
2048游戏就是相同的数字相互翻倍叠加,从最开始的2开始到4再到8最后一直可以叠加到2048,具体玩法如下:
1、刚打开游戏的界面,有两个2,并且我们需要知道每次移动后都会出现一个2,只有相同的数才能相加,也就是每次合并之后数据都会翻倍。
2、这个游戏最关键的思想是要形成一种势,就大数在一边,小数在一边,这样相同的数才能更好的结合在一起。
3、当玩的数据比较大的时候就需要形成S形。
4、将上图的S形依次从小推上去!这样就轻松的形成了第一个2048。
注意事项
玩的时候最好是时刻让最右边一排或者两排是满的,这样上下移动的时候,最右边一排形成的局势就不会破坏。同时除了在不得已的情况,千万别向左移动。
c语言猜数字游戏源代码
小游戏2048:
#includestdio.h
#includestdlib.h
#includeconio.h
#includetime.h
#includewindows.h
int jsk( ); //计算空格数
void rsgm( ); //重置游戏
void inkey( ); //按键输入
void left( ); //向左移动
void right( ); //向右移动
void up( ); //向上移动
void down( ); //向下移动
void show( ); //输出界面
void adnum( ); //添加随机数
void yes( ); //游戏是否结束(1是0否)
void gtxy(int x, int y); //控制光标位置的函数
int a[4][4]; //存储16个格子中的数字
int score = 0; //每局得分
int best = 0; //最高得分
int ifnum; //是否需要添加数字(1是0否)
int over; //游戏结束标志(1是0否)
int i,j,k;
int main( )
{ rsgm( ); //重置游戏
inkey( ); //按键输入
return 0;
}
void Color(int a) //设定字符颜色的函数(a应为1-15)
{ SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE),a); }
void rsgm( ) //重置游戏
{ score = 0; ifnum = 1; over = 0; srand((unsigned)time(0)); //启动随机数发生器
int n = rand( ) % 16; //随机函数产生0-15的数字
for (i = 0; i 4; i++)
{for (j = 0; j 4; j++)
{ if (n == 0) { int k = rand( ) % 3; if (k == 0 || k == 1) { a[i][j] = 2; }
else { a[i][j] = 4; } n--; }
else { a[i][j] = 0; n--; }
}
}
adnum( );
system("cls");
CONSOLE_CURSOR_INFO gb={1,0}; //以下两行是隐藏光标的设置,gb代指光标
SetConsoleCursorInfo( GetStdHandle(STD_OUTPUT_HANDLE), gb );
Color(14); //设置字体淡黄色
printf("\n\n\t\t 2048小游戏"); Color(7); //恢复白字黑底
printf("\n\t┌──────┬──────┬──────┬──────┐");
printf("\n\t│ │ │ │ │");
printf("\n\t├──────┼──────┼──────┼──────┤");
printf("\n\t│ │ │ │ │");
printf("\n\t├──────┼──────┼──────┼──────┤");
printf("\n\t│ │ │ │ │");
printf("\n\t├──────┼──────┼──────┼──────┤");
printf("\n\t│ │ │ │ │");
printf("\n\t└──────┴──────┴──────┴──────┘");
show( );
}
void show( ) //输出界面
{ for(i=0;i4;i++)
for(j=0;j4;j++)
{ gtxy(7*j+9,2*i+4); //gtxy(7*j+9, 2*i+4)是光标到指定位置输出数字
if(a[i][j]==0){printf(" "); Color(7); printf("│");}
else if(a[i][j]10){ if (a[i][j] == 2) { Color(14); }
else if (a[i][j] == 4) { Color(13); }
else if (a[i][j] == 8) { Color(12); }
printf(" %d ", a[i][j]); Color(7 ); printf("│");
}
else if (a[i][j] 100){if (a[i][j] == 16) { Color(12); }
else if (a[i][j] == 32) { Color(10); }
else if (a[i][j] == 64) { Color(2 ); }
printf(" %d ", a[i][j]); Color(7); printf("│");
}
else if (a[i][j] 1000) {if (a[i][j] == 128) { Color(9); }
else if (a[i][j] == 256) { Color(1); }
else if (a[i][j] == 512) { Color(13); }
printf(" %d ", a[i][j]); Color(7); printf("│");
}
else if (a[i][j] 10000) {if (a[i][j] == 1024) { Color(5); }
else { Color(15); }
printf(" %d ", a[i][j]); Color(7); printf("│");
}
}
if (jsk( ) == 0)
{ yes( ); if (over) { gtxy(9,12); Color(10);
printf("\n\n 游戏结束!是否继续? [ Y/N ]:"); }
}
}
void inkey( ) //按键输入
{ int key;
while (1)
{ key = getch( );
if (over) { if (key == 89|| key == 121) { rsgm( ); continue; }
else if (key == 78|| key == 110) { return; }
else continue; }
ifnum = 0;
if(key==224)key=getch( );
switch (key)
{ case 75: left( ); break;
case 77: right( ); break;
case 72: up( ); break;
case 80: down( );break;
}
if (score best) { best = score; }
if (ifnum) { adnum( ); show( ); }
}
}
int jsk( ) //计算空格数
{ int n = 0;
for (i = 0; i 4; i++)
{ for (j = 0; j 4; j++) { if ( a[i][j] == 0) {n++;} } }
return n;
}
void left( ) //向左移动
{ for (i = 0; i 4; i++)
{for (j = 1, k = 0; j 4; j++)
{ if (a[i][j] 0)
{ if ( a[i][k] == a[i][j])
{ a[i][k] *= 2; k++;
score = score + 2 * a[i][j];
a[i][j] = 0; ifnum = 1; }
else if ( a[i][k] == 0) { a[i][k] = a[i][j]; a[i][j] = 0; ifnum = 1; }
else { a[i][k + 1] = a[i][j]; if ((k + 1) != j) { a[i][j] = 0; ifnum = 1; }
k++; }
}
}
}
}
void right( ) //向右移动
{for (i = 0; i 4; i++)
{for (j = 2, k = 3; j = 0; j--)
{if (a[i][j] 0)
{ if (a[i][k] == a[i][j])
{a[i][k] *= 2; k--; score = score + 2 * a[i][j]; a[i][j] = 0; ifnum = 1; }
else if ( a[i][k] == 0) {a[i][k] = a[i][j]; a[i][j] = 0; ifnum = 1; }
else { a[i][k - 1] = a[i][j]; if ((k - 1) != j) { a[i][j] = 0; ifnum = 1; } k--; }
}
}
}
}
void up( ) //向上移动
{for (i = 0; i 4; i++)
{for (j = 1, k = 0; j 4; j++)
{if (a[j][i] 0)
{if ( a[k][i] == a[j][i]) { a[k][i] *= 2; k++;score = score + 2 * a[j][i];
a[j][i] = 0; ifnum = 1; }
else if ( a[k][i] == 0) { a[k][i] = a[j][i]; a[j][i] = 0; ifnum = 1; }
else { a[k + 1][i] = a[j][i]; if ((k + 1) != j) { a[j][i] = 0; ifnum = 1; }
k++; }
}
}
}
}
void down( ) //向下移动
{ for (i = 0; i 4; i++)
{for (j = 2, k = 3; j = 0; j--)
{if (a[j][i] 0)
{if (a[k][i] == a[j][i])
{a[k][i] *= 2; k--;score = score + 2 * a[j][i]; a[j][i] = 0; ifnum = 1; }
else if (a[k][i] == 0) {a[k][i] = a[j][i]; a[j][i] = 0; ifnum = 1; }
else {a[k - 1][i] = a[j][i];
if ((k - 1) != j) {a[j][i] = 0; ifnum = 1; } k--; }
}
}
}
}
void adnum( ) //添加随机数
{ srand(time(0)); int n = rand( ) % jsk( );
for (int i = 0; i 4; i++)
{for (int j = 0; j 4; j++)
{ if (a[i][j] == 0) {if (n != 0) { n--; }
else {int k = rand( ) % 3;
if (k == 0 || k == 1) {a[i][j] = 2; return; }
else {a[i][j] = 4; return; } }
}
}
}
}
void yes( ) //游戏是否结束
{ for (int i = 0; i 4; i++)
{for (int j = 0; j 3; j++)
{if (a[i][j] == a[i][j + 1] || a[j][i] == a[j + 1][i]) {over = 0; return; }}
}
over = 1;
}
void gtxy(int x, int y) //控制光标位置的函数
{ COORD zb; //zb代指坐标
zb.X = x;
zb.Y = y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), zb);
}
急求游戏2048源代码,要求使用C++和HGE编写,充分体现面向对象编程的特点。
一看就知道是作业,具体代码还是自己写吧,我可以给一些思路。
构建一个类来存储矩阵的状态,以及操作(上下左右)的代码,一个简单的实现方案是只需要写向一个方向移动的代码,然后通过转换矩阵的方向来实现其他的方向。
面向对象嘛你,可以父类定义N*N矩阵,只实现一个移动方向,子类通过继承实现4*4矩阵,和各个移动方向。
关于2048安卓源代码和2048程序的介绍到此就结束了,不知道你从中找到你需要的信息了吗 ?如果你还想了解更多这方面的信息,记得收藏关注本站。
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